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  • 25-04-2018
  • Mathematics
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Аноним Аноним
  • 25-04-2018
[tex]f(x) = \dfrac{x}{2} - 2[/tex]

[tex]g(x) = 2x^2 + x - 3[/tex]

[tex](f + g)(x) = \dfrac{x}{2} - 2+ 2x^2 + x - 3[/tex]

[tex](f + g)(x) = 2x^2 + \dfrac{3}{2}x - 5[/tex]
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