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An aqueous solution is prepared by mixing 0.2750 moles of naoh (40.00 g mol-1) with 189.0 g of water. its density is 1.065 g ml-1. the solute is completely dissociated. what is the percent by weight of naoh in the solution?

Respuesta :

The weight of NaoH=moles of NaOH where 
Molar mass = 0.2750×40=11g
Mass of solution = (189+11) = 200g
So mass in pertcentage of NaoH =(11/200)×100=5.5%

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