Respuesta :

jushmk
Induced emf = -NA (ΔФ/Δt)

N = 1 (assuming its 1 loop), ΔФ = 0.2-0 = 0.2 T, Δt = 0.3 sec, A = 0.12 m^2

Therefore,

Induced emf = -1*0.12*(0.2/0.3) = -0.08 V