GhostElite8240 GhostElite8240
  • 23-10-2017
  • Mathematics
contestada

If arrivals occur at a mean rate of 3.6 events per hour, the exponential probability of waiting more than 0.5 hour for the next arrival is:

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W0lf93
W0lf93 W0lf93
  • 01-11-2017
The answer is 0.8347. Mean u = 1/m = 3.6 per hour Time x = 0.5 hour Exponential Probability = P(X <= x) Going by the Cumulative distribution function P(X <= x) = 1 - e^(-mx) P(X < .5) = 1 – exp^(-3.6 x 0.5) = 1 – 0.1653 = 0.8347
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