Seudónimo Seudónimo
  • 23-10-2017
  • Mathematics
contestada

how would the expression x^3-3sqrt(3) be rewritten using difference of cubes?

how would the expression x33sqrt3 be rewritten using difference of cubes class=

Respuesta :

zenton222 zenton222
  • 23-10-2017
The difference of two cubes is factored by
x^3-y^3=(x-y)(x^2+xy+y^2)

In this case it would be

C) 
Answer Link
erato erato
  • 08-04-2019

Answer:

Correct option is:

C. [tex](x-\sqrt{3})(x^2+3+x\sqrt{3} )[/tex]

Step-by-step explanation:

x^3-3sqrt(3)

=  [tex]x^3-3\sqrt{3} \\\\=x^3-\sqrt{3}^3[/tex]

= [tex](x-\sqrt{3})(x^2+3+x\sqrt{3} )[/tex]

(since, [tex]a^3-b^3=(a-b)(a^2+b^2+ab)[/tex])

Hence, the correct option is:

   C.    [tex](x-\sqrt{3})(x^2+3+x\sqrt{3} )[/tex]

Answer Link

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