how does finding the square root of a number compare to finding the cube root of a number. Use the number 64 in your explanation.

Can someone please help me with this?

Respuesta :

if [tex]x^2=y[/tex] , then [tex]\sqrt[2]{y}=\sqrt[2]{x^2}=x[/tex]

if [tex]x^3=y[/tex] , then [tex]\sqrt[3]{y}=\sqrt[3]{x^3}=x[/tex]


ok
[tex]64=8^2=4^3[/tex]

so
[tex]\sqrt[2]{64}=\sqrt[2]{8^2}=8[/tex]
[tex]\sqrt[3]{64}=\sqrt[3]{4^3}=4[/tex]

well, the cube root usually bigger