duffh
duffh
23-08-2017
Mathematics
contestada
Need help on this one guyss asap
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mreijepatmat
mreijepatmat
23-08-2017
Sample space ={1,2,3,4,5,6}
P(one "6) = 1/6
Q(NOT getting any "6) = 5/6
⁴C₂(P)²(Q)² = ⁴C₂(1/6)²(5/6)² = ⁴C²(25/1296)
⁴C₂ = (4!)/(2!)(2!) = 6
Then Probability(getting 2 "6" in 4 rolls) = 6(25/1296) = 25/216 = 0.1157
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