Respuesta :

2KI(aq) + Pb(NO₃)₂(aq) = PbI₂(s) + 2KNO₃(aq)

Pb²⁺(aq) + 2I⁻(aq) = PbI₂(s)

The lead iodide precipitate is formed in the reaction.

Answer: to observe both solutions before the reaction

Explanation: