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22-04-2017
Mathematics

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k^{2} -9 \k^{2} -7k+12

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22-04-2017

[tex] \frac{k^2-9}{k^2-7k+12} [/tex] Factor
= [tex]\frac{(k+3)(k-3)}{(k-3)(k-4) }[/tex] Eliminate (k-3)
=[tex]}\frac{(k-3)}{(k-4) }[/tex] Isolate k

k-3=0
k=3

k-4=0
k=4

k is equal to 3,4

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