Respuesta :

[tex]\bf \begin{array}{llll} \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}\\ ----------\\ \textit{surface area of a sphere}\\\\ S=4\pi r^2 \end{array}\qquad r=radius\\\\ -----------------------------\\\\ V=1928\implies 1928=\cfrac{4\pi r^3}{3}\implies \cfrac{3\cdot 1928}{4\pi }=r^3 \\\\\\ \sqrt[3]{\cfrac{3\cdot 1928}{4\pi }}=\boxed{r}\qquad thus \\\\\\ S=4\pi \left( \boxed{\sqrt[3]{\cfrac{3\cdot 1928}{4\pi }}} \right)^2[/tex]