contestada

How many grams of Tin (SN) would be required to use 6.9 moles of chlorine (cl2)

Respuesta :

Sn  +  Cl₂   →  SnCl₂

mole ratio of Cl₂  :  Sn  is   1 :  1
∴ if moles of Cl₂  =  6.9 mol
 then moles of Sn = 6.9 mol

Mass =  moles × molar mass

          =  6.9 mol  × 119 g/mol
 
          =  821.1 g