itsjuan2360 itsjuan2360
  • 24-11-2022
  • Chemistry
contestada

how many moles of gas are in 30.0 l of a contained tube with a temperature of 300.k and pressure at 200. atm? use r

Respuesta :

rlhessonr rlhessonr
  • 25-11-2022

Answer:

234.61 mol

Explanation:

According to the Ideal Gas Law:

PV=nRT

P= 200 atm

V= 30.0 L

T= 300 K

R= 0.0821 [tex]\frac{(atm)(L)}{(mol)(K)}[/tex]

[tex]n=\frac{PV}{RT}[/tex]

[tex]n=\frac{(200atm)(30.0L)}{0.0821\frac{(atm)(L)}{(mol)(K)}(300K)}\\n=234.61 mol[/tex]

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