KyedenG452042 KyedenG452042
  • 26-10-2022
  • Mathematics
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Find the equation of the line passing through the points (3,-2) and (4,6)

Find the equation of the line passing through the points 32 and 46 class=

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LondynH486415 LondynH486415
  • 26-10-2022

The equation is of the form y = mx + b, where m is the slope and b is the y-intercept. Therefore:

- For m:

Given the points (3, -2) and (4, 6)

[tex]m=\frac{y2-y1}{x2-x1}=\frac{6-(-2)}{4-3}=\frac{6+2}{1}=\frac{8}{1}=8[/tex]

- For b:

We use the point (4,6)

[tex]\begin{gathered} y=mx+b \\ 6=8(4)+b \\ 6=32+b \\ 6-32=32+b-32 \\ b=-26 \end{gathered}[/tex]

Substitute the values, so the equation is:

[tex]y=8x-26[/tex]

Answer: y = 8x - 26

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