What is the sum?A. 9 + (–11)B. –16 + (–8)C. –6 + 2D. 1/8+(-2/3)If you can, please show your work/how you got it, thanks. (⌒_⌒;)

Respuesta :

Answer:

(a)-2 (b)-24 (c)-4 (d)-13/24

Explanation:

Part A

First, we open the bracket. Take note that:

• - x - = +

,

• - x + = -

So:

[tex]9+(-11)=9-11=-2[/tex]

Part B

[tex]\begin{gathered} -16+(-8)=-16-8 \\ =-24 \end{gathered}[/tex]

Part C

[tex]\begin{gathered} -6+2=2-6 \\ =-4 \end{gathered}[/tex]

Part D

[tex]\frac{1}{8}+(-\frac{2}{3})=\frac{1}{8}-\frac{2}{3}[/tex]

Next, we take the lowest common multiple of the denominators: 8 and 3

L.C.M. of 8 and 3 = 24

We then have:

[tex]\begin{gathered} \frac{3-2(8)}{24}=\frac{3-16}{24} \\ =-\frac{13}{24} \end{gathered}[/tex]