To answer this question, we need to sum each of the hours Kevin will practice.
Then, we have that Kevin will practice:
Monday = 1 + 1/2 hours.
Tuesday = 1 + 3/4 hours.
Wednesday = 2 hours.
Next week, Kevin will practice again the same hours:
Monday = 1 + 1/2 hours.
Tuesday = 1 + 3/4 hours.
Wednesday = 2 hours.
On these six days, Kevin will practice:
[tex](1+\frac{1}{2})+(1+\frac{3}{4})+2+(1+\frac{1}{2})+(1+\frac{3}{4})+2[/tex]And we can add the whole numbers first:
[tex](1+1+2)+(\frac{1}{2}+\frac{3}{4})+(1+1+2)+\frac{1}{2}+\frac{3}{4}[/tex][tex]4+(\frac{1}{2}+\frac{3}{4})+4+(\frac{1}{2}+\frac{3}{4}_{})[/tex]Then, to solve the fractions, we can proceed as follows:
Now, we have:
[tex]4+\frac{5}{4}+4+\frac{5}{4}=(4+4)+(\frac{5}{4}+\frac{5}{4})=8+\frac{10}{4}=8+\frac{5}{2}[/tex]Summing the last two numbers:
[tex]\frac{16+5}{2}=\frac{21}{2}=10.5[/tex]
