Alex dropped a coin from a height of 240 feet.
How long, in seconds, will it take for the object to reach the ground?
This is a free-fall motion and we can use the equations of motion to find out the time.
Recall from the equations of motion,
[tex]h=ut+\frac{1}{2}gt^2[/tex]
Where h is the height, u is the initial velocity, g is the gravitational acceleration, and t is the time.
We know that the initial velocity is 0 since the coin was at rest before it was dropped.
So, we have the following values
h = 240 feet
u = 0 m/s
g = 9.8 m/s²
Let us substitute these values into the above equation of motion and solve for t
[tex]\begin{gathered} h=ut+\frac{1}{2}gt^2 \\ 240=(0)t_{}+\frac{1}{2}(9.8)t^2 \\ 240=\frac{1}{2}(9.8)t^2 \\ \frac{2\cdot240}{9.8}=t^2 \\ 48.98=t^2 \\ \sqrt{48.98}=t \\ 6.998=t \\ t=7 \end{gathered}[/tex]
Therefore, it will take 7 seconds for the object to reach the ground.
