Respuesta :
The Slope-Intercept form of the equation of a line is:
[tex]y=mx+b[/tex]Where "m" is the slope and "b" is the y-intercept.
You can find the slope of the line with this formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]For this case you can set up that:
[tex]\begin{gathered} y_2=-1 \\ y_1=11 \\ x_2=-4 \\ x_1=-1 \end{gathered}[/tex]Substituting values into the formula, you get that the slope of this line is:
[tex]m=\frac{-1-11}{-4-(-1)}=\frac{-12}{-4+1}=\frac{-12}{-3}=4[/tex]Substitute the slope and one of the coordinates of one of the points on the line, into the equation
[tex]y=mx+b[/tex]And solve for "b":
[tex]\begin{gathered} -1=4(-4)+b \\ -1=-16+b \\ -1+16=b \\ b=15 \end{gathered}[/tex]Therefore, knowing "m" and "b", you can determine that the equation of this line in Slope-Intercept form is:
[tex]y=4x+15[/tex]