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What is the position vector of the midpoint of the line PQ if P has coordinates(-13,-4,6) and Q has coordinates (0,4,11)?OA. ( 130 - 17)B.(-13,0,1)c. (2.0.1D. (-2,0. - 1)

Respuesta :

The general formula to find the midpoint of a line in a 3D space is given by

[tex]M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2},\frac{z_1+z_2}{2})[/tex]

In this case, we have

[tex]M=(\frac{-13+0}{2},\frac{-4+4}{2},\frac{6+11}{2})=(\frac{-13}{2},0,\frac{17}{2})[/tex]

So the position vector of the midpoint of the line PQ is

[tex]M=(-\frac{13}{2},0,\frac{17}{2})[/tex]

which is option B.

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