AydeG104942 AydeG104942

25-10-2022
Mathematics

contestada

What is sqrt 12x^8 / sqrt 3x^2 in simplest form, where x≥0?

Respuesta :

AryehQ87428 AryehQ87428

25-10-2022

we have

[tex]\frac{\sqrt[]{12x^8}}{\sqrt[]{3x^2}}=\sqrt[]{\frac{12x^8}{3x^2}=\sqrt[]{\frac{12}{3}\frac{x^8}{x^2}}}\text{ = }\sqrt[]{4x^6}=\sqrt[]{4}\sqrt[]{x^6}=2x^3[/tex]

answer:

[tex]2x^3[/tex]

Answer Link

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