can you please solve this practice problem for me I really need assistance with this practice problem.

Answer:
C.
[tex]y=\frac{1}{3}x+1[/tex]Explanation:
The slope-intercept form of the equation of a line is given as;
[tex]y=mx+b[/tex]where m = slope of the line
b = y-intercept of the line.
Let's go ahead and determine the slope of the given line at (-3, 0) and (3, 2) where x1 = -3, y1 = 0, x2 = 3, and y2 = 2 using the below formula;
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ =\frac{2-0}{3-(-3)} \\ =\frac{2}{6} \\ \therefore m=\frac{1}{3} \end{gathered}[/tex]From the given line, we can see that the y-intercept, b, is +1.
Since m = 1/3 and b = 1, our equation of the line can then be written as;
[tex]y=\frac{1}{3}x+1[/tex]