2 5 4 Q Find the area of the shaded region above.

As you can see in the given figure, there are two different shapes.
One is a rectangle and the other is a triangle.
Recall that the area of a rectangle is given by
[tex]A_R=L\cdot W[/tex]Where L is the length and W is the width.
As you can see from the figure,
W = 4
L = 5
So the area of the rectangle is
[tex]A_R=L\cdot W=5\cdot4=20[/tex]Recall that the area of a triangle is given by
[tex]A_T=\frac{1}{2}\cdot b\cdot h[/tex]Where b is the base of the triangle and h is the height of the triangle.
As you can see from the figure,
b = 4
h = 2
So the area of the triangle is
[tex]A_T=\frac{1}{2}\cdot b\cdot h=\frac{1}{2}\cdot4\cdot2=\frac{1}{2}\cdot8=\frac{8}{2}=4[/tex]Now the total area of the shaded region is the sum of the area of the rectangle and the area of the triangle.
[tex]A=A_R+A_T=20+4=24[/tex]Therefore, the area of the shaded region is 24
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