Given:
The population of a town increases by 9 % annually.
The current population is 4,500.
Required:
We need to find the equation that gives the population of the town.
Explanation:
The population can be found by the following equation.
[tex]Th\text{e population =4500+9 \% of 4500}[/tex]
Let now be the current population of the town =4500.
Let Next be the population of the town.
The population can be found by the following equation.
[tex]Next\text{ =Now+9\% of Now.}[/tex]
[tex]Next\text{ =Now+}\frac{9}{100}\times\text{Now.}[/tex]
Take the common term now out.
[tex]Next\text{ =Now\lparen1+}\frac{9}{100})[/tex][tex]Use\text{ }\frac{9}{100}=0.09.[/tex]
[tex]Next\text{ =Now\lparen1+0.09})[/tex]
[tex]Next\text{ =Now\lparen1.09})[/tex]
[tex]Next\text{ =Now}\times\text{1.09}[/tex]
Final answer:
[tex]Next\text{ =Now}\times\text{1.09}[/tex]
