Respuesta :
Answer:
The correct answer is:
The ordered pair (2, 3) is not a solution to the system.
Explanation:
The system given is:
[tex]\begin{cases}3x+7y={1} \\ 2x+4y={0}\end{cases}[/tex]If (2, 3) is a solution of the system, then replacing x = 2 and y = 3 on both equations should give a correct result and the same on both equatiions.
In the first equation;
[tex]\begin{gathered} 3\cdot2+7\cdot3=1 \\ 6+21=1 \\ 27=1 \end{gathered}[/tex]We can see that this result is not true, as 27 is not equal to 1.
In the second equation:
[tex]\begin{gathered} 2\cdot2+4\cdot3=0 \\ 4+12=0 \\ 16=0 \end{gathered}[/tex]Once again, a false result.
To see in the system has equations, let's solve for x in the second equation:
[tex]\begin{gathered} 2x+4y=0 \\ 2x=-4y \\ x=-2y \end{gathered}[/tex]Now, we can use substitution in the first equation:
[tex]3(-2y)+7y=1[/tex]And solve for y:
[tex]\begin{gathered} -6y+7y=1 \\ y=1 \end{gathered}[/tex]Now, we can find the value of x:
[tex]x=-2\cdot1=-2[/tex]The solution to the system is (-2, 1)
Thus, the correct option is "The ordered pair (2, 3) is not a solution to the system"
