LissandraY483598 LissandraY483598

25-10-2022
Mathematics

contestada

8in 8in 8in area of irregular figures

Respuesta :

AsahelH88147 AsahelH88147

25-10-2022

Given data:

The given figure.

The expression for the area is,

[tex]\begin{gathered} A=(8\text{ in)(8 in)+}\frac{1}{2}(8\text{ in)( 8 in)} \\ =96in^2 \end{gathered}[/tex]

Thus, the area of the given ffigure is 96 square-inches.

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