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A ball is thrown in the air. It's height, h (in meters).is given by h = -4.91 +306 + 6 where is thetime (in seconds). What is the height of the ballafter 3 seconds?

Respuesta :

The given equation-

[tex]-4.9t^2+30t+6[/tex]

After three seconds, we evaluate for t = 3.

[tex]-4.9(3)^2+30(3)+6=-4.9(9)+90+6=-44.1+96=51.9[/tex]

Therefore, the height after 3 seconds is 51.9 meters.

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