Suppose medical records indicate that the length of a newborn babies(in inches) is normally distributed with a mean of 20 and a standard deviation of 2.6 point find the probability that a given infant is between 17.4 and 22.6 inches long?

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Answer:

P(17.4 < X < 22.6) = P((X-20)/2.6 < (22.6-20)/2.6) = P(Z < 1.38)

From a standard normal table, we find that P(Z < 1.38) = 0.9128

Step-by-step explanation:

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