The fraction at pH 10.00 = 0.850
When the moles of base added equal half the total moles of acid, the weak acid and its conjugate base are in equal amounts. The CB/WA ratio is one, and pH = pKa + log(1) or pH = pKa according to the HH equation.
The fraction of dissociation, can be calculated directly as x / F. At this concentration, the acid is dissociated 99.9% of the time! Calculate the pH of a 0.0500 M solution for a weak acid HA with pKa = 2.328.
pH 10.00
the formula for [tex]\frac{\left[\mathrm{NH}_3\right]}{\left[\mathrm{NH}_3\right]+\left[\mathrm{NH}_4^{\dagger}\right]}[/tex] and the value for Ka solve for the[H₃O⁺]
first :
pH = -log[H₃O⁺]
[H₃O⁺] = 10^-pH
[H₃O⁺] = 1 x 10^-10
solve for the[tex]\frac{\left[\mathrm{NH}_3\right]}{\left[\mathrm{NH}_3\right]+\left[\mathrm{NH}_4^{\dagger}\right]}[/tex]
[tex]\frac{\left[\mathrm{NH}_3\right]}{\left.\mathrm{NH}_4^{+}\right]+\left[\mathrm{NH}_3\right]}=\frac{K_a}{\left[\mathrm{H}_3 \mathrm{O}^{+}\right]+K_a}[/tex]
[tex]=\frac{5.68 \times 10^{-10}}{1 \times 10^{-10}+5.68 \times 10^{-10}}[/tex]
= 0.850
the fraction at pH 10.00 = 0.850
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