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Help Please!!!!

What is the distance from the hazard buoy P to the southern landmark L2? Use this formula: d^2=(DL2)^2+(PD)^2 , where d is the distance from P to L2, DL2 is the distance from D to L2, and PD is the distance from P to D. Round to the nearest foot. (5 points)

DL2 = 600ft
PD = 700ft

Help Please What is the distance from the hazard buoy P to the southern landmark L2 Use this formula d2DL22PD2 where d is the distance from P to L2 DL2 is the d class=

Respuesta :

Answer:

922 ft

Step-by-step explanation:

[tex]d^{2}=PD^{2}+D_{2}L^{2}\\\ \ \ \ \\ =\ 600^{2}+700L^{2}\\\ \ \ \ \\ =\ 850000\\\\\text \\then\\d = \sqrt{850000} =921.954445729289\\\\\text then\\d\ \approx922[/tex]

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