keirnanbrown2132 keirnanbrown2132
  • 25-03-2022
  • Mathematics
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Find a whole number $a$ such that the numbers $\frac{2}{a}$ , $\frac{a}{8}$ , and $63\%$ are in order from least to greatest

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LammettHash
LammettHash LammettHash
  • 25-03-2022

If 2/a, a/8, and 63% = 63/100 are in numerical order, then

2/a < a/8 < 63/100

Multiply each "side" of the inequality by 8a :

16 < a² < 126a/25

a has to be a whole number, and since 4² = 16, we must have at least a ≥ 5.

Divide through by a :

16/a < a < 126/25 = 5 + 1/25

Then at most, a ≤ 5.

So, both a ≥ 5 and a ≤ 5, which means a = 5.

Just to check that the list is in order, we have

2/a = 2/5 = 0.4

a/8 = 5/8 = 0.625

and 0.4 < 0.625 < 0.63.

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