Caligirl187 Caligirl187

22-03-2022
Mathematics

contestada

Evaluate the following logarithms. log12144 = log151 = log3 ( 1 81 ) = log 0.00001 =

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lmaisunny lmaisunny

22-03-2022

Answer:

Answer(s): (2,0,-4,-5)

log12 144 = 2

log15 1 = 0

log3 ( 1/ 81 ) = -4

log 0.00001 = -5

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