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if 2 rectangles are divided in equal parts and 1/3of 1 is shaded and 1/4of the other is shaded.what is the least number of parts into wich both could be divided into

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Josuke
I believe it's 12 parts? Because 1 third would be 4/12 and 1 fourth would be 3/12.
think of it as pie one is split into thirds and one split into fourths  then combine them so you should have a pie split into sixths shade two of spaces(representing the one 1\3 and 1\4 so you should have 4\6 spaces left(2\3 left and 3\4 left) and boom your answer your welcom