highskye1
contestada

PLEASE HELP!!!
Yuri thinks that 3/4 is a root of the following function. q(x) = 6x3 + 19x2 – 15x – 28 Explain to Yuri why 3/4 cannot be a root.

Respuesta :

lilydoesallthin
The answer is The root of a number x is another number, which when multiplied by itself a given number of times, equals x. For example the second root of 9 is 3, because 3x3 = 9. The second root is usually called the square root. The third root is susually called the cube root See Root (of a number). because then/

3/4 cannot be a factor because none of the factors of 6 which is the q value are four. The factors of the p value, in this case 28, must go over one of the q values