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A 2 kg mass of copper is heated for 40 seconds by a heater which produces 100J/s and the SHC of the copper is 400J what is the rise in temperature

Respuesta :

Answer/Explanation:

m= 2kg

t= 40s

P= 100J/s

C= 400J/kg°C

Q= P×t

= 100×40= 4000J

Q= m×C×∆t

4000= 2×400×∆t

∆t= 4000/(2×400)

∆t= 5°C

P stands for power

Q is heat energy, and we know that power multiplied by time gives amount of energy (which in this case is heat energy)

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