Respuesta :

darkness880826

Answer:

[tex]3a^{b} *\sqrt{3} +2a*\sqrt{3b}[/tex]

Step-by-step explanation:

[tex]\sqrt{3^{2}*3a^{2b} } +a*\sqrt{2^{2} *3b} \\\sqrt{3^{2} *a^{2b} *3} +a(\sqrt{2^{2} *\sqrt{3b} } )\\[/tex]

Result:

[tex]3a^{b} *\sqrt{3} +2a*\sqrt{3b}[/tex]