Three identical blocks connected by ideal (massless) strings are being pulled along a horizontal frictionless surface by a horizontal force F⃗ F → .
The magnitude of the Force is 4.5 N
The objective of the question is to determine the magnitude of the force.
From the given information;
- Since the tension in the string of blocks B and C is drawing blocks A and B, Then, acceleration will be equal.
∴
[tex]\mathbf{F=(m_A + m_B) a}[/tex]
where;
- Force F = 3.00 N
- mass = 0.400 kg
[tex]\mathbf{3=(0.400 + 0.400) a}[/tex]
[tex]\mathbf{a = \dfrac{3}{0.800 }}[/tex]
a = 3.75 m/s²
Now, the magnitude of the Force in the whole system is determined as follows:
∴
[tex]\mathbf{F = (m_a+m_b+m_c )a}[/tex]
F = (0.400 +0.400+0.400) × 3.75
F = 1.2 × 3.75
F = 4.5 N
Therefore, we can conclude that the magnitude of the Force is 4.5 N
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