Respuesta :

Answer:  78.69 g of Fe

Explanation:  Iron(III) oxide is Fe2O3.  It has a molar mass of 159.7 g/mole.  That consists of:

2 x Fe at 55.85 = 11.69  or 69.94%

3 x O at 16.0 = 48.0        or 30.06%

Therefore 112.5 grams will contain (112.5 g)*(69.94%) = 78.69 g of Fe