Respuesta :
Step-by-step explanation:
[tex] = > \frac{ {x}^{2} + 1 }{x + 2} \equiv \frac{A}{x + 2} \\ {x}^{2} + 1 = A \\ when \: x = 0 \\ A = 1 \\ \frac{ {x}^{2} + 1}{x + 2} = \frac{1}{x + 2} [/tex]
Step-by-step explanation:
[tex] = > \frac{ {x}^{2} + 1 }{x + 2} \equiv \frac{A}{x + 2} \\ {x}^{2} + 1 = A \\ when \: x = 0 \\ A = 1 \\ \frac{ {x}^{2} + 1}{x + 2} = \frac{1}{x + 2} [/tex]