amenberhane77 amenberhane77

22-05-2021
Mathematics

contestada

In Figure 5.51 given to the right, m( <ABC) =
32°, m(<BHE) = 42° and m( <ADE) = 48°
Find m(<NAD).

In Figure 551 given to the right m ltABC 32 mltBHE 42 and m ltADE 48Find mltNAD class=

Respuesta :

mohamedruham35 mohamedruham35

22-05-2021

Answer:

122

Step-by-step explanation:

<HEB=180-(42+32)

=180-74

=106

<DEA=180-106 (straight line)

=74

<NAD=48+74(exterior angle = sum of 2 interior opposite angles)

<NAD=122

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