Evaluate 2a^2 – 3ab + b^2 – 4a + b when a = - 4 and b = – 2.
-6
74
18
26
Please no links

Answer:
26
Step-by-step explanation:
Substitute -4 for a and -2 for b
[tex]2a^{2} - 3ab+b^{2}-4a-b\\ 2(-4^{2} )- 3 (-4*-2)+-(2^{2})-4(-4)-2 \\32-24+4+16-2[/tex]