Answer:
1.1 × 10² g
Explanation:
Step 1: Given data
- Concentration of the solution (C): 0.50 M (0.50 mol/L)
- Volume of solution (V): 1500 mL (1.500 L)
Step 2: Calculate the moles of Mg(NO₃)₂ (solute)
Molarity is equal to the moles of solute (n) divided by the liters of solution.
C = n/V
n = C × V
n = 0.50 mol/L × 1.500 L = 0.75 mol
Step 3: Calculate the mass corresponding to 0.75 moles of Mg(NO₃)₂
The molar mass of Mg(NO₃)₂ is 148.3 g/mol.
0.75 mol × 148.3 g/mol = 1.1 × 10² g
