A spring has a natural length of 20cm. If a 25-N force is required to keep it stretched to a length of 30 cm, how much work is required to stretch it from 20 cm to 25 cm?

Respuesta :

First, we use Hooke's Law to calculate the spring constant, k:
F = kx
k = 25 / (0.3 - 0.2)
k = 250 N/m

Work = 1/2 kx²
W = 1/2 x 250 x (0.25 - 0.2)²
W = 0.3125 Joule

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