An experiment consists of rolling two fair(not weighted) dice and adding the dots on the two sides facing up. Each die has the number 1 on two opposite faces, the number 2 on two opposite faces, and the number 3 on two opposite faces.
Compute the probability of obtaining the indicated sums in problem.
Just regular dice, it has total possible outcomes. You will see there are 12 of them have a total of 4, if you would see. So, the answer would be 12/36=1/3
the rest can also be obtained by counting. the probability you get a sum of 2 is
4/36
So, for a sum of 6
and the probability you get a sum of 3 and the probability you get a sum of 5 is
8/36
