blexi6108 blexi6108

26-03-2021
Chemistry

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What is the new pressure of 160 mL of a gas that is compressed to 50 mL when the pressure was 4.0 atm and the temperature is held constant?

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21ahmedfa 21ahmedfa

26-03-2021

P1V1 = P2V2
P1 = 4.0 atm
V1 = 160 mL
P2 = ?
V2 = 50 mL

Solve for P2 —> P2 = P1V1/V2 = (4.0)(160)/(50) = 12.8 atm

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