Respuesta :

Convert grams of silver nitrate to moles using the molar mass of AgNO3.

10.0 g AgNO3 • 1 mol AgNO3 / 169.87 g AgNO3 = 0.0589 mol AgNO3

Molarity is mol/L so divide the moles of AgNO3 by liters of solution.

0.0589 mol AgNO3 / 0.5 L = 0.118 M AgNO3