Answer:
- The mass of the liquid displaced is 0.12 kg
- The buoyant force on the block is 1.176 N.
Explanation:
Given;
density of water, ρ = 1.0 g/cm³
volume of the submerged block, V = 120 cm³
Applying Archimedes principle;
The mass of the liquid displaced is calculated as;
m = ρV
m = 1.0 g/cm³ x 120 cm³
m = 120 g
m = 0.12 kg
The buoyant force on the block is calculated as;
F = mg
F = 0.12 x 9.8
F = 1.176 N
Therefore, the buoyant force on the block is 1.176 N.
