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Suppose that 20% of students at high school A and 18% of students at high school B participate on a school athletic team. Independent random samples of 30 students from each school are selected and asked if they participate on a school athletic team. Let ˆ p A represent the sample proportion of students at school A who participate on a school athletic team and ˆ p B represent the sample proportion of students at school B who participate on a school athletic team.

What is the mean of the sampling distribution of ˆ p A − ˆ p B ?

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Answer:

0.02

Step-by-step explanation:

High schools A :

Percentage of participants in on the school athletic team = 20%

Pa = 20% = 0.2

High school B:

Percentage of participants in on the school athletic team = 18%

Pa = 18% = 0.18

The mean of sampling distributon is :

Pa - Pb

0.2 - 0.18

Hence, Mean of sampling distribution is 0.02

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