RenRenCool RenRenCool

25-10-2020
Mathematics

contestada

Find the root of the equasion
(2y+1)^2–4y^2=5

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serenavass serenavass

25-10-2020

Answer:

the root of the equation is y=1

Step-by-step explanation:

[tex](2y + 1)^{2} - 4 {y}^{2} = 5 \\ 4 {y}^{2} + 2 \times 2y \times 1 + {1}^{2} - 4 {y}^{2} = 5 \\ 4y + 1 = 5 \\ 4y = 5 - 1 \\ 4y = 4 \\ y = 1[/tex]

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