ron-59 is a beta emitter with a half-life of 44.5 days. If a sample initially contains 144 mg of iron-59, how much iron-59 is left in the sample after 213 days?

Respuesta :

Answer:

5.22 mg

Explanation:

Half life is the amount of time taken for a substance to reduce to half of its initial value. The half life is calculated using:

[tex]N=N_0(\frac{1}{2} )^{\frac{t}{t_{1/2}} }\\\\N_0=initial\ amount\ of\ substance,N=final\ amount\ of\ substance,t_{1/2}=half-life, t=time\ elapsed\\\\Given\ that\ N_0=144mg, t=213\ days,t_{1/2}=44.5\ days\\\\N=N_0(\frac{1}{2} )^{\frac{t}{t_{1/2}} }\\\\N=144\ mg*(\frac{1}{2} )^{\frac{213\ days}{44.5\ days} }\\\\N=5.22\ mg[/tex]