The 7-digit numbers 74A52B1 and 326AB4C are each multiples of 3. Which of the following could be the value C?

A(1) B(2) C(3) D(5) E(8)

Question

kawaiiangelgirl kawaiiangelgirl

24-09-2016
Mathematics

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The 7-digit numbers 74A52B1 and 326AB4C are each multiples of 3. Which of the following could be the value C?

A(1) B(2) C(3) D(5) E(8)

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rabinshrestha41 rabinshrestha41 · Answer 1 · 2016-09-24T05:06:54+02:00

74A52B1 and 326AB4C are multiples of 3.....That means if we divide them by 3, we should get a whole number.

Lets assume A=1 and B=1,
So,
74A52B1 becomes 7415211

Now, lets divide it by 3.
7415211 / 3 = 2471737

Since we got a whole number as a quotient, we can safely say that A=1 and B=1.

∴ The second number 326AB4C becomes 326114C.

Now, lets assume C = 1.
So,
326114C becomes 3261141.
Now,
lets divide it by 3.

3261141 / 3 = 1087047

Since we got a whole number as a quotient, C = 1

∴The value of C is 1. So, answer choice A is correct.

The 7-digit numbers 74A52B1 and 326AB4C are each multiples of 3. Which of the following could be the value C? A(1) B(2) C(3) D(5) E(8)

Respuesta :

Otras preguntas

The 7-digit numbers 74A52B1 and 326AB4C are each multiples of 3. Which of the following could be the value C?

A(1) B(2) C(3) D(5) E(8)