mariz4L8illika
mariz4L8illika
22-09-2016
Mathematics
contestada
\[y^{\prime\prime} 4y=\cos2x\]
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kramermccauslan
kramermccauslan
29-09-2016
So the question if find y'' for 4y=cos2x
First, find y by dividing by 4. y = cos2x/4
Then, take the first derivative. y' = -sin2x/2
Then, take the second dervative. y'' = -cos2x
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